From charlesreid1

(Created page with "{{FMM |title=A Binomial Problem |problem= <math> \binom{16}{4} = \binom{16}{2r+1} </math> Find r. |answer= First, if we solve it naively, we get r = 2r + 1 -r = 1 r = -...")
 
 
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<math>
 
<math>
 
\binom{16}{4} = \binom{16}{2r+1}
 
\binom{16}{4} = \binom{16}{2r+1}
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</math>
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Find r.
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Challenge problem:
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<math>
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\binom{120}{r} = \binom{120}{3r+4}
 
</math>
 
</math>
  
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This is something we may implicitly assume, due to our own understanding of the nature of the binomial numbers and Pascal's Triangle. We just have to cover all our bases.
 
This is something we may implicitly assume, due to our own understanding of the nature of the binomial numbers and Pascal's Triangle. We just have to cover all our bases.
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Challenge problem:
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r = (120 - 4)/(1 + 3) = 29
  
 
}}
 
}}

Latest revision as of 10:32, 4 December 2019

Friday Morning Math Problem

A Binomial Problem


\binom{16}{4} = \binom{16}{2r+1}

Find r.

Challenge problem:


\binom{120}{r} = \binom{120}{3r+4}

Find r.

Solution
{{{solution}}}

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