## Problem Statement

This problem explores an extension of the concept of a triangular number, generated by the formula $\dfrac{n(n+1)}{2}$, to other shapes.

Exploring triangle, square, pentagonal, hexagonal, heptagonal, and octagonal numbers - numbers that are generated according to particular formulae:

$P_{3,n} = \dfrac{n(n+1)}{2}$

$P_{4,n} = n^2$

$P_{5,n} = \dfrac{n(3n-1)}{2}$

$P_{6,n} = n(2n-1)$

$P_{7,n} = \dfrac{n(5n-3)}{2}$

$P_{8,n} = n(3n-2)$

## Solution Technique

CURRENTLY UNSOLVED

Our solution technique is to generate a graph (for this, we use the Guava library).

We wish to find the sum of the ordered set of six cyclic 4-digit numbers for which each polygonal type, triangle/square/pentagonal/hexaongal,/heptagonal,octagonal, is represented by a different permutation of the digits (maintaining original order).

To do this, we create a graph, with each possible connection between a prefix and a suffix marked with an edge.

This results in a 6-partite graph, and we seek a path, a cycle, that passes through all 6 partitions.