From charlesreid1

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T_c = \dfrac{8a}{27bk}
T_c = \dfrac{8a}{27bk}
</math>
</math>
Start by rearranging to get P as a function of T and V.


Find the two expressions, now you have two equations and two unknowns Vc and Tc.
Find the two expressions, now you have two equations and two unknowns Vc and Tc.

Revision as of 03:15, 22 May 2016

Background

Critical points of gas, supercritical behavior

The Van Der Waal equation for a gas accounts for non-ideal behavior caused by strong intermolecular forces of attraction or repulsion:

$ (P + \dfrac{a}{V^2})(V-b) = kT $

where P is the pressure, V is the molar volume (volume of a certain number of moles), a and b are constants that depend on the molecules, k is the Boltzmann constant, and T is temperature.

Now the critical points can be found: https://www.youtube.com/watch?v=VjVQxzxxLVw

Critical point is the saddle point of the above equation, and is defined as the point where:

$ \dfrac{\partial P}{\partial V} \bigg|_{T=T_c,V=V_c} = 0 $

and

$ \dfrac{\partial^2 P}{\partial V^2} \bigg|_{T=T_c,V=V_c} = 0 $

Question 1

Show that the critical point $ (P_c, V_c, T_c) $ is given by:

$ P_c = \dfrac{a}{27b^2} $

$ V_c = 3b $

$ T_c = \dfrac{8a}{27bk} $

Start by rearranging to get P as a function of T and V.

Find the two expressions, now you have two equations and two unknowns Vc and Tc.

Solve for these two quantities.

Finally, you know Pc as a function of Vc and Tc.