Project Euler/312
From charlesreid1
Problem Statement
A Sierpiński graph of order-1 ($ S_1 $) is an equilateral triangle.
$ S_{n + 1} $ is obtained from $ S_n $ by positioning three copies of $ S_n $ so that every pair of copies has one common corner.
Let $ C(n) $ be the number of cycles that pass exactly once through all the vertices of $S_n$.
For example, $ C(3) = 8 $ because eight such cycles can be drawn on $ S_3 $, as shown below:
It can also be verified that:
$ C(1) = C(2) = 1 $
$ C(5) = 71328803586048 $
$ C(10\,000) \bmod 10^8 = 37652224 $
$ C(10\,000) \bmod 13^8 = 617720485 $
Find $ C(C(C(10\,000))) \bmod 13^8 $
Notes
This problem is asking about Hamiltonian cycles on Sierpinski graphs.
The problem combines elements of graph theory, combinatorics, and fractal geometry.
Key concepts:
- Graph theory fundamentals
- Definition of a graph
- Cycles and paths
- Hamiltonian cycles (precise definition is important - cycle visiting every vertex precisely once)
- Graph properties (number of vertices and edges as function of recursion level)
- Sierpinsky Graphs
- Recursive construction ($ S_{n+1} $ in terms of $ S_n $)
- Vertex and edge growth
- Vertex degrees
- Hamiltonian Cycle Theory
- Recursion and mathematical induction
- Exploiting recursive structure is central principle for Sierpinski graphs
- Inductive proofs (arguments based on the recursion level n, base case of 0 or 1)
- Recursive counting: how to construct Hamiltonian cycles in $ S_{n+1} $ from those in $ S_n $, recurrence relation would be a formula for H(n+1) in terms of H(n) (and potentially other related counts), where H(n) is number of hamiltonian cycles in S(n)
- Combinatorial Counting
- Recurrence relation may require using standard techniques
- Symmetry: Sierpinsky graphs possess significant symmetry (rotational/reflectional), so exploiting this symmetry can potentially greatly reduce counting arguments. This looks like counting "real different" cycles, and multiplying by a symmetry factor.
- Casework within recursion: when constructing a cycle in $ S_{n+1} $ from $ S_n $, need to analyze how cycle traverses connections between the $ S_n $ copies, which might involve careful casework depending on which corner vertices are entry/exit points
Possible Strategy
C(C(C(10_000))) mod 13^8 indicates you don't compute full values, but instead exploit mathematical properties:
- Periodicity:
- check if the sequence C(n) (mod M) becomes periodic at some point.
- If a period P can be found, then C(X) (mod M) = C(X (mod P)) (mod M)
- Chinese Remainder Theorem if M is composite, or properties relate to powers of primes (such as 13^8)
- Matrix exponentiation:
- If recurrence C(n) is linear homogeneous recurrence, such as C(n) = a*c(n-1) + b*C(n-2), then it can be solved with matrix exponentiation
- Technique works extremely well with modular arithmetic
- Allows computing C(N) (mod M) even for very large N in O(log N) matrix multiplications
- Fixed points or specific properties:
- Specific property related to C, and modulus 13^8, potentially?
- C(n) (mod M) might converge to a fixed point for large n,
- C(n) (mod M) might simplify greatly if n is a value modulo M,
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