FMM4
From charlesreid1
Friday Morning Math Problem
The Zeta Monogram
Mrs. and Mrs. Zeta are expecting a new (genderneutral) baby. They wish to name their baby such that the baby's monogram (first initial, middle initial, last initial) is in alphabetical order with no letter repeated. (For example, ABZ is a valid monogram, but BBZ and QBZ are not.) How many possible monograms are there?
Solution 

The Zeta family wants little baby Zeta to have a monogram (first initial, middle initial, last initial) that is alphabetical with no letters repeated. The last letter of the monogram must be Z. If the first letter is A, that leaves 26  2 = 24 possible letters, ABZ, ACZ, etc. If the first letter is B, that leaves 23 possible letters, BCZ, BDZ, etc. If we repeat this for all possibilities we will get 24 + 23 + 22 + ...
Using the formula n(n+1)/2 we can see that 24 + 23 + ... = 24*25/2 = 300

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